Respuesta :

Answer:

B

Step-by-step explanation:

[tex]\frac{3+4\iota}{2+4\iota}=\frac{3+4 \iota}{2+4\iota} \times \frac{2-4 \iota}{2-4 \iota}\\=\frac{6 -12 \iota+8 \iota-16 \iota^2  }{4-16 \iota^2  }\\=\frac{ 6-4 \iota+16}{4+16}\\=\frac{22-4 \iota}{20}[/tex]