Respuesta :
[tex]\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\quad
\begin{cases}
r=radius\\
h=height\\
-----\\
r=3\\
h=4
\end{cases}\implies V=\cfrac{\pi 3^2\cdot 4}{3}\implies V=12\pi [/tex]
now, when she closed the funnel and filled it up, that's how much liquid it took in. Then it's dripping 12 in³ every minute, how long will it take to lose all the volume?
[tex]\bf \begin{array}{ccll} in^3&minute\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 12&1\\ 12\pi &m \end{array}\implies \cfrac{12}{12\pi }=\cfrac{1}{m}\implies m=\cfrac{12\pi \cdot 1}{12}[/tex]
now, when she closed the funnel and filled it up, that's how much liquid it took in. Then it's dripping 12 in³ every minute, how long will it take to lose all the volume?
[tex]\bf \begin{array}{ccll} in^3&minute\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 12&1\\ 12\pi &m \end{array}\implies \cfrac{12}{12\pi }=\cfrac{1}{m}\implies m=\cfrac{12\pi \cdot 1}{12}[/tex]