Respuesta :
the diagonals of a rhombus are perpendicular bisectors of each other, and are also angle bisectors. The 4 congruent right triangles the rhombus is cut into by the two diagonals are 30-60-90 degree triangles, the longer leg is √3/2 of the hypotenuse, √3/2 of 10=5√3. so the longer diagonal is twice of 5√3=10√3
The length of the longer diagonal of the rhombus is 10[tex]\sqrt{3}[/tex].
What is a rhombus?
'In plane Euclidean geometry, a rhombus is a quadrilateral whose four sides all have the same length.'
According to the given problem,
Length of each side of the rhombus = 10
Measure of angle = 60°
In the right angled triangle AOD,
∠OAD = 30°
∠AOD = 90°
AD = 10
⇒ cos 30 = [tex]\frac{Base}{Hypotenuse}[/tex]
⇒ cos 30 = [tex]\frac{OA}{10}[/tex]
⇒ 10 × [tex]\frac{\sqrt{3} }{2}[/tex] = OA
⇒ 5[tex]\sqrt{3}[/tex] = OA
We know, in the rhombus ADCB,
Longer diagonal, AC = 2 × AO
Therefore,
Longer diagonal = 2 × 5[tex]\sqrt{3}[/tex]
= 10[tex]\sqrt{3}[/tex]
Hence, we can conclude, the length of the longer diagonal is 10[tex]\sqrt{3}[/tex].
Learn more about rhombus here: https://brainly.com/question/21871409
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