Respuesta :
Answer:
either y = 4.5
or y = -4.5
Explanation:
To get the solution, we will need to isolate the y on one side of the equation.
This can be done as follows:
4y² = 81
[tex] \frac{4y^2}{4} = \frac{81}{4} [/tex]
y² = 20.25
y = +/- √(20.25)
either y = +√(20.25) = 4.5
or y = -√(20.25) = -4.5
Since there are no restrictions on the value of y, therefore, both answers would be accepted
Hope this helps :)
either y = 4.5
or y = -4.5
Explanation:
To get the solution, we will need to isolate the y on one side of the equation.
This can be done as follows:
4y² = 81
[tex] \frac{4y^2}{4} = \frac{81}{4} [/tex]
y² = 20.25
y = +/- √(20.25)
either y = +√(20.25) = 4.5
or y = -√(20.25) = -4.5
Since there are no restrictions on the value of y, therefore, both answers would be accepted
Hope this helps :)
Answer:
y = ± 4.5.
Step-by-step explanation:
Given : 4y²=81
To find : Solve for y
Solution : We have given that
4y²=81
On dividing by 4 both sides
y²= [tex]\frac{81}{4}[/tex]
y²= 20.25
On taking square root both sides
y = [tex]\sqrt{20.25}[/tex]
y = ± 4.5
Therefore, y = ± 4.5.