Answer:
Step-by-step explanation:
The perimeter is the sum of the four side lengths of the rectangle. If L and W represent the length and width, respectively, then there are two sides of length L and two sides of length W. This means the perimeter is ...
2L +2W, or 2(L+W)
The problem statement tells us the perimeter is 110 cm, so if all lengths are in cm, the equation for perimeter can be ...
2(L+W) = 110 . . . . equation for the perimeter
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The problem statement also gives a relationship between length and width. Twice the width will be represented by 2W, so one more cm than that will be (2W+1). We are told that is the same as the length:
2W+1 = L . . . . . equation relating length and width
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Solution (not required by the problem statement)
Substituting the second equation into the first, you get
2(2W+1 +W) = 110
3W+1 = 55 . . . . . divide by 2
3W = 54 . . . . . . .subtract 1
W = 18 . . . . . . . . .divide by 3
L = 2·18+1 = 37
