Respuesta :
I will solve the question assuming the reaction used as below
1 CH4(g) + 1 H2O(g) ==> 1 CO(g) + 3 H2(g)
In the reaction, CH4 is the reactant and CO is the wanted product. If you look at the coefficient of the substance, for every 1 mol of CH4 react there will be 1 mol of CO produced. So, if you have 7 moles of CH4 the amount of CO produced would be: 7 moles * 1/1= 7 moles of CO
1 CH4(g) + 1 H2O(g) ==> 1 CO(g) + 3 H2(g)
In the reaction, CH4 is the reactant and CO is the wanted product. If you look at the coefficient of the substance, for every 1 mol of CH4 react there will be 1 mol of CO produced. So, if you have 7 moles of CH4 the amount of CO produced would be: 7 moles * 1/1= 7 moles of CO
Answer:
7 moles of CO
Solution:
Methane when treated with water in the presence of catalyst (i.e. Nickle) and high temperature.
produces Carbon monoxide and Hydrogen gas as shown below,
CH₄ + H₂O → CO + 3 H₂
According to this equation,
1 mole of CH₄ produces = 1 mole of CO
So,
7 moles of CH₄ will produce = X moles of CO
Solving for X,
X = (7 mole × 1 mole) / 1 mole
X = 7 moles of CO