A car with a mass of 1000kg isat rest at a stoplight. When the light turns green, it is pushed by a net force of 2000 N for 10 s.

What is the value of the change in velocity that the car experiences?

Respuesta :

2000= 1000a
a=2m/s^2
v=2*10=20m/s

Answer: 20 m/s

Explanation:

First of all, we can calculate the acceleration of the car by using Newton's second law:

[tex]F=ma[/tex]

where F is the net force on the car, m is the mass, a is the acceleration. Using m=1000 kg and F=2000 F, we find the acceleration

[tex]a=\frac{F}{m}=\frac{2000 N}{1000 kg}=2 m/s^2[/tex]

The acceleration is also equal to the ratio between the change in velocity and the time taken:

[tex]a=\frac{\Delta v}{\Delta t}[/tex]

Since we know the time taken, [tex]\Delta t=10 s[/tex], we can re-arrange the formula to find the change in velocity of the car:

[tex]\Delta v=a \Delta t=(2 m/s^2)(10 s)=20 m/s[/tex]