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A proton and an electron are moving due east in a constant electric field that also points due east. the electric field has a magnitude of 4.0 × 104 n/c. determine the magnitude of the acceleration of the proton and the electron.

Respuesta :

calculista
First we calculate the Electric Force

F = qE = 1.6E-19 * 4 E+4 = 6.4 E -15 N

This Force is equal to mass*acceleration

F = m*a

Mass of the electron = 9.1 E-31 Kg

Mass of the proton = 1.67 E -27 Kg

Acceleration of electron =  6.4 E -15 / 9.1 E -31 = 7.033 E 15 [m/s**2]

Acceleration of proton =  6.4 E -15 / 1.67 E -27 = 3.832 E 12 [m/s**2]

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