Respuesta :
On the 8x > –32 first divide by the 8 from the both sides.
8x/8 as a fractions and it is greater than negative 32/8 as a fraction. And the equals to x is greater than negative 4.
On the 6x ≤ –48. Then divide by 6 from the both sides.
6x/6 as a fractions and it is less than negative 48/6 as a fraction. And the equals to x≤ negative 8.
8x/8 as a fractions and it is greater than negative 32/8 as a fraction. And the equals to x is greater than negative 4.
On the 6x ≤ –48. Then divide by 6 from the both sides.
6x/6 as a fractions and it is less than negative 48/6 as a fraction. And the equals to x≤ negative 8.
Answer:
(-∞,-8] U (-4,∞)
Step-by-step explanation:
[tex]8x > -32 \ or \ 6x\leq-48[/tex]
To solve the compound inequality we solve each inequality and combine the solutions
[tex]8x > -32[/tex]
Divide both sides by 8
[tex]x>-4[/tex]
[tex]6x\leq-48[/tex]
Divide both sides by 6 to get x alone
[tex]x\leq-8[/tex]
Now we combine both inequalities
[tex]x>-4[/tex] or [tex]x\leq-8[/tex]
WE combine both inequalities
(-∞,-8] U (-4,∞)
