What is the area of this figure?
49.5 in²
66.5 in²
84 in²
91 in²

The given figure can be divided in two parts 1) Square with side 7 in 2) A right triangle with base 12 in and height 7 in.
1) Area of square = [tex] side^{2} [/tex]
Side of the square is 7 in.
Area = [tex] 7^{2} =49in^{2} [/tex]
2) Area of triangle = [tex] \frac{1}{2} .base . height [/tex]
Area of triangle =[tex] \frac{1}{2} (12)(7) =42in^{2} [/tex]
Area of polygon= Area of square+ Area of triangle
Area of polygon = 49+42 =91 square in.
Area = [tex] 91in^{2} [/tex]