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What is the volume occupied by 3.00 × 1023 molecules of bromine gas at STP?

a 404.5 L

B. 0.80 L

C. 2.2 × 10-2

D. 11.2 L

Respuesta :

D. 11.2 L , since we are at STP we will use the ideal gas law. 3.0 x 10²³ 6.02x10²³ / 1 mole and if you continue with this process it will give you 11 L.
simrahali15

Answer:

The answer is 11.2 L.

Explanation:

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