A. The two triangles ABC and EDC are similar using AA similarity criterion.
B. The width of the river is 145.45 ft.
Given information:
Kayla walks along the edge of the river 100ft and marks point C. Then she walks 22ft further and marks point D. She turns 90 degrees and walks until her location, point A, and point C are collinear. She marks point E at this location.
A. The two right triangles ABC and CDE are made.
In the two triangles, angles D and B are equal to 90 degrees.
Also, angle DCE and angle ACB are equal because they are vertically opposite angles.
Using AA similarity rule, triangle ABC is similar to triangle EDC.
B. Suppose DE = 32ft. It is required to calculate the width AB of the river.
The value of AB can be calculated as,
[tex]\dfrac{AB}{DE}=\dfrac{BC}{CD}\\\dfrac{AB}{32}=\dfrac{100}{22}\\AB=145.45\rm\; ft[/tex]
Therefore, the width of the river is 145.45 ft.
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