Answer:
Ques 1)
(-2,12)
Ques 2)
The solution is: (4,1)
Ques 3)
The solution is:
(-4,1)
Ques 4)
The solution is: (-3, 3)
Ques 5)
The solution is: (1,-2)
Step-by-step explanation:
Ques 1)
We have to solve the following system of equation using elimination method.
{5x+y=2
4x+y=4
we will subtract equation (2) from first to obtain:
5x-4x=2-4
x= -2
Now on putting the value of x in first equation we obtain:
5×(-2)+y=2
-10+y=2
y=2+10
y=12
Hence, the solution is:
(-2,12)
Ques 2)
Now again we have to solve using linear combination method.
{2d−e=7
d+e=5
we will add both the equations to get:
2d+d=12
3d=12
d=4
and on putting the value of d in second equation we obtain:
4+e=5
e=5-4
e=1
Hence,
C. The solution is (4, 1).
Ques 3)
5x−y=−21
x+y=−3
we will add both the equation to obtain:
5x+x=-21-3
6x = -24
x= -4
and on putting the value of x in equation (2) we get:
-4+y = -3
y= -3+4
y=1
Hence, the solution is:
(-4,1)
Ques 4)
−3x+9y=36
4x+12y=24
we will divide first equation on both side by 3 and second equation on both side by 4 to obtain the system as:
-x+3y=12
x+3y=6
on adding both the equations we get:
3y+3y=12+6
i.e. 6y=18
i.e. y=3
Hence on putting the value of y in one of the equation we obtain:
x= -3
Hence, the solution is:
(-3,3)
Ques 5)
7/2x−1/2y=9/2
3x−y=5
on multiplying both side of the equation by 2 we obtain:
7x-y=9
Now on subtracting second equation from this transformed equation we obtain:
7x-3x=9-5
4x=4
x=1
Hence on putting the value of x in one of the equations we obtain the value of y as:
y= -2
Hence, the solution is:
(1, -2)
Answer:
It was (-2,12)
Step-by-step explanation:
Just took the test that was the answer
