Respuesta :

The solution to the given system of equations is
m = 7
n = 2

The given equations are

5m+3n=41

3m-6n=9

To solve the equations by linear combination method we make the coefficient of m or n same in both equation. To make coefficient of n same we multiply the first equation by 2

2[5m+3n=41 ]

Multiplying both sides by 2 we have:

10m+6n=82

3m-6n=9 ( second equation)

Adding the two equation the variable n is eliminated

13m=91

Dividing both sides by 13

m=7.

Substituting m value in the first equation we have:

5m+3n=41

5(7)+3n=41

35+3n=41

Subtracting 35 both sides

3n=41-35

3n=6

Dividing both sides by 3

n=2.

Answer:

M=7.N= 2.