What is the point-slope form of a line that has a slope of 5 and passes through the point (3, –4)?
y – 3 = 5[x – (–4)]
–4 – y1 = 5(3 – x1)
y – (–4) = 3(x – 5)
y – (–4) = 5(x – 3)
The generic form for this case is given by y = m (x-xo) + yo where xo: x coordinate me: y coordinate Substituting the values we have y = 5 (x-3) - 4 Therefore, the answer in this case is y – (–4) = 5(x – 3)
