The length of the larger rectangle is x+4, and the length of the smaller one is x.
The proportions of the widths and the lengths have to be the same; thus, we can create an equation.
[tex] \frac{5}{3} = \frac{x+4}{x} [/tex]
On the left side, multiply both the numerator and denominator by 2. Now, we have
[tex] \frac{10}{6} = \frac{x+4}{x} [/tex]
Set the numerators equal to the numerator and denominator equal to the denominator.
x+4=10
x=6
Both of these equations are true when x=6, which is our answer. Hope this helps! :)
