ok let's do this*pops knuckles*
let's add the first side
[tex]1 + 2 \times 3 - 18[/tex]
order of operations demands that we do multiplication first(P.E.M.D.A.S)
so
[tex]2 \times 3 = 6[/tex]
now we can add the 1 from
[tex]1 + (6) - 18[/tex]
into our six
[tex]6 + 1 = 7[/tex]
now we substract
[tex](7) - 18 = - 11[/tex]
now we have
[tex] - 11 \div 3 + (5(2 + 2))[/tex]
now we focus on the
other side
[tex]3 + (5(2 + 2))[/tex]
since 5 is in paranthesis we use something called the distributive property. it mean we will multiply the 5 by both of the 2.
[tex](5(2 + 2)) = (((5 \times 2) + (5 \times 2) = 20[/tex]
now we have
[tex]3 + 20 = 23[/tex]
(the three is from the original equation)
now we plug in our final numbers
[tex] - 11 \div 23[/tex]
or
[tex] \frac{ - 11}{23} [/tex]
I hope this helps
