Respuesta :
Answer:
3,307.72 kilo Joules is required to ionize 2.52 moles of hydrogen atoms.
Explanation:
[tex]E_n=-13.6\times \frac{Z^2}{n^2}eV[/tex]
[tex]E_n[/tex] = energy of [tex]n^{th}[/tex] orbit
n = number of orbit
Z = atomic number
We have : Z = 1
Energy of electron when n=1 is given as:
[tex]E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV[/tex]
Energy of electron when n=1 is given as:
[tex]E_{infty }=-13.6\times \frac{1^2}{\infty ^2}eV=0 eV[/tex]
Ionization energy of single hydrogen atom:
[tex]I.E =E_{\infty }-E_1=0 eV - (-13.6 eV)=13.6 eV[/tex]
[tex]1 eV=1.60218\times 10^{-22} kJ[/tex]
[tex]13.6 eV=13.6\times 1.60218\times 10^{-22} kJ=2.179\times 10^{-21} kJ[/tex]
Moles of hydrogen atoms = 2.52 mol
[tex]1 mole = 6.022\times 10^{23} [/tex] atoms/molecules
Atoms in 2.52 moles of hydrogen:
[tex]2.52\times 6.022\times 10^{23} atoms=1.518\times 10^{24} atoms[/tex]
Ionization energy of single hydrogen atom: [tex]2.179\times 10^{-21} kJ[/tex]
Energy required to ionize 2.52 moles of hydrogen atoms:
[tex]1.518\times 10^{24}\times 2.179\times 10^{-21} kJ=3,307.72 kJ[/tex]
3,307.72 kilo Joules is required to ionize 2.52 moles of hydrogen atoms.
