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Answer: The integers are 52,53,54.

Step-by-step explanation:

Let the three consecutive integers are

[tex]x,x+1,x+2[/tex]

Since we have given that

The sum of the first two is 51 more than the third,

According to question,

[tex](x+x+1)-(x+2)=51\\\\2x+1-x-2=51\\\\x-1=51\\\\x=51+1\\\\x=52[/tex]

So, the three consecutive integers are

52,52+1,52+2

52,53,54.

Hence, the integers are 52,53,54.


The consecutive integers are [tex]\boxed{52}, \boxed{53}[/tex] and [tex]\boxed{54}[/tex] if the sum of two is 51 more than the third.

Further explanation:

The numbers that have a difference of 1 between every next number is known as the consecutive  

Explanation:

The sum of the first two is 51 more than the third.

Consider the first number of consecutive integers as [tex]\text{p}[/tex].

So the second number of consecutive integers is [tex]\text{p}+1.[/tex]

Therefore, the third number of consecutive integers is [tex]\text{P}+2[/tex]

The sum of first two numbers is 51 more than the third.

[tex]\begin{aligned}\left( x \right) + \left( {x + 1} \right) &= 51 + \left( {x + 2} \right)\\x + x + 1 &= 51 + x + 2\\2x + 1 &= 53 + x \\2x - x &= 53 - 1\\x&= 52\\\end{aligned}[/tex]

The first number of consecutive integers is 52.

The second number of consecutive integer can be obtained as follows,

[tex]\begin{aligned}{\text{Second integer}} &= p + 1\\&= 52 + 1\\&= 53\\\end{aligned}[/tex]

The third number of consecutive integer can be obtained as follows,

[tex]\begin{aligned}{\text{Third integer}} &= p + 2\\&= 52 + 2\\&= 54\\\end{aligned}[/tex]

The consecutive integers are [tex]\boxed{52}, \boxed{53}[/tex] and [tex]\boxed{54}[/tex] if the sum of two is 51 more than the third.

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Answer details:

Grade: High school

Subject: Mathematics

Chapter: Linear equation

Keywords: consecutive, three consecutive, sum, addition, integers, more, 51 more, consecutive integers, first two.