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An impulse of 150 n s is required to stop a person's head in a car collision. if the face is in contact with the steering wheel for 0.0307 s, what is the average force on the cheekbone? answer in units of n.

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Blitztiger
We can divide the impulse by the time to determine the average force. Given an impulse of 150 N-s, and a contact time of 0.0307 s, the average force is:
150 N-s / 0.0307 s = 4886 N

Note that the impulse is the change in momentum, so they have the same units of N-s or kg-m/s.

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