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a professional baseball player can pitch a baseball with a velocity of 44.7m/s towards home plate. If a baseball weighs 1.4 N, how much momentum does it have when it hits the catcher units

Respuesta :

aachen

Answer:

p = 6.25 kg-m/s

Explanation:

It is given that,

Velocity of the baseball, v = 44.7 m/s

Weight of the baseball, W = 1.4 N

Firstly we need to find the mass of the baseball. It can be calculated as :

[tex]m=\dfrac{W}{g}[/tex]

[tex]m=\dfrac{1.4\ N}{9.8\ m/s^2}[/tex]

m = 0.14 kg

The momentum of an object is equal to the product of mass and velocity. It is given by :

[tex]p=m\times v[/tex]

[tex]p=0.14\ kg\times 44.7\ m/s[/tex]

p = 6.25 kg-m/s

So, the momentum it have when it hits the catcher is 6.25 kg-m/s. Hence, this is the required solution.

Lanuel

The amount of momentum the baseball has when it hits the catcher is 6.39 Kgm/s.

Given the following data:

  • Velocity = 44.7 m/s
  • Weight of baseball = 1.4 Newton

We know that acceleration due to gravity (g) is equal to 10 meter per seconds square.

To find the amount of momentum the baseball has when it hits the catcher:

First of all, we would determine the mass of the baseball.

Mathematically, the weight of an object is given by the formula;

[tex]Weight = mg[/tex]

Where;

  • m is the mass of the object.
  • g is the acceleration due to gravity.

[tex]1.4 = mass \times 9.8\\\\Mass = \frac{1.4}{9.8}[/tex]

Mass = 0.1429 kg

Now, we can calculate the momentum the baseball:

Mathematically, momentum is given by the formula;

[tex]Momentum = mass \times velocity\\\\Momentum = 0.1429 \times 44.7[/tex]

Momentum = 6.39 Kgm/s

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