The salt produced is [tex]Na_2SO_4[/tex]. The reaction between a strong acid and a strong base results in salt and water. Since the base and acid are strong the reaction goes to completion. The balanced equation is:
[tex]H_2SO_4 _(_a_q_) + NaOH_(_a_q_) ==> Na_2SO_4_(_a_q_) + 2H_2O_(_l_)[/tex]
In fact this is a neutralization reaction in which [tex]Na^+[/tex] and [tex]SO_4^-^2[/tex] are spectator ions.
[tex]2H^+ _(_a_q_)+ + SO_4^-^2 _(_a_q_) + 2Na^+ _(_a_q_) +2OH^- ==> 2Na^+ _(_a_q_) + SO_4^-^2 _(_a_q_) + 2H_2O _(_l_)[/tex],
If you remove the spectactor ions, [tex]Na^+[/tex] ions and [tex]SO_4^-^2[/tex] on both sides of the equation, then the net ionic equation is,
[tex]2H^+ _(_a_q_) + 2OH^- _(_a_q_) ==> 2H_2O _(_l_)[/tex]
