Chloroform (CHCl3), an important solvent, is produced by a reaction between methane and chlorine. CH4(g) + 3 Cl2(g) CHCl3(g) + 3 HCl(g) How many grams of CH4 is needed to produce 66.5 g CHCl3?
CH4 +3Cl2 ---> CHCl3 + 3 HCl one molecules of CH4 reacted with 3 molecules of Cl to form one molecule of CHCl3 and 3 molecules of HCl
this implies that the ratio of CH4 to CHCl3 is 1:1
the moles of CHCl3 formed=66.5/119.5(molar mass of CHCl3) =0.556 moles since ratio is 1:1 the moles of CH4 is also 0.556moles mass=moles x molar mass mass=0.556 x 16(molar mass of CH4)= 8.896grams
