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Blitztiger
The charge of an electron is -1.602 x 10^-19 Coulombs. If an average lightning bolt carries around 10.0 Coulombs of charge, we can simply divide this by the charge of an electron to estimate the total number of excess electrons:

(10.0 C) / (1.602 x 10^-19 C/electron) = 6.24 x 10^19 electrons
So there are around 6.24 x 10^19 excess electrons in a typical lightning bolt.

The [tex]6.25\times 10^{19}[/tex]  excess electrons are present in a typical lightning bolt that has 10 C of charge.

Coulomb:

It is the number of electrons transported in one second by a current of one ampere. It is measured in metre-kilogram-second-ampere. It is denoted by C.

The formula of Coulomb is

[tex]C = As[/tex]

Where,

[tex]C[/tex] = coulomb

[tex]A[/tex] = amperes

[tex]s[/tex] = seconds  

The excess electrons,

[tex]= \dfrac {10}{1.6\times 10^{-19 }}\\\\= 6.25\times 10^{19}[/tex]

Therefore, the [tex]6.25\times 10^{19}[/tex]  excess electrons are present in a typical lightning bolt that has 10 C of charge.

To know more about Coulomb:

https://brainly.com/question/4111722

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