Respuesta :
Answer : The molarity of the solution is, 0.365 mole/L
Solution : Given,
Mass of [tex]Na_3PO_4[/tex] (solute) = 15 g
Volume of solution = 250 ml
Molarity : It is defined as the number of moles of solute present in one liter of the solution.
Formula used :
[tex]Molarity=\frac{\text{Moles of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}[tex]
Now put all the given values in this formula, we get the molarity of the solution.
[tex]Molarity=\frac{15g\times 1000}{163.94g/mole\times 250ml}=0.365mole/L[/tex]
Therefore, the molarity of the solution is, 0.365 mole/L
The molarity of the solution is equal to 0.365 M.
First, to calculate the molarity of 15 grams of the compound diluted in 250 ml, the molar mass of the molecule must be calculated, having:
[tex]MM Na_{3}PO_{4} = 3 \times MM [Na]+ MM [P] + 4 \times MM[O][/tex]
[tex]MM Na_{3}PO_{4} = 3 \times 23 + 31 + 4 \times 16[/tex]
[tex]MM Na_{3}PO_{4} = 164 g/mol[/tex]
Now, calculate the number of moles present in 15 grams of the substance, so that:
[tex]moles = \frac{g}{MM}[/tex]
[tex]moles = \frac{15}{164}[/tex]
[tex]moles = 0.09mol[/tex]
Finally, as the molarity of a compound is due to the number of moles present in a liter, perform the following expression:
1000 ml = 1L
[tex]\frac{0.09mol}{xmol} =\frac{250ml}{1000ml}[/tex]
[tex]x = 0.365 M[/tex]
So, the molarity of the compound is equal to 0.365 mol per liter.
Learn more about mole calculation in: brainly.com/question/15693285
