A regular hexagon has sides of 3 feet. What is the area of the hexagon?

Answer:
[tex]13.5\sqrt{3}\:\text{ft}^{2}[/tex]
Step-by-step explanation:
Given: The side of a regular hexagon is 3 feet.
To find: Area of the hexagon
Solution:
It is given that the side of a regular hexagon is 3 feet.
We know that the area of a regular hexagon whose side is a units is [tex]\frac{3\sqrt{3} }{2} a^{2}[/tex]
Here, the side is 3 feet
So, area of the regular hexagon
[tex]=\frac{3\sqrt{3} }{2} \times3^{2}[/tex]
[tex]=\frac{3\sqrt{3} }{2} \times9[/tex]
[tex]=\frac{27\sqrt{3} }{2}[/tex]
[tex]=13.5\sqrt{3}\:\text{ft}^{2}[/tex]
Hence, area of the regular hexagon is [tex]13.5\sqrt{3}\:\text{ft}^{2}[/tex]