Respuesta :
Answer:
molarity = 0.385 moles/kg
Explanation:
Assume that the volume of the aqueous solution given is 1 liter = 1000 ml
Now, density can be calculated using the following rule:
density = mass / volume
Therefore:
mass = density * volume = 1.23 * 1000 = 1230 grams
Now, 0.467 m/L * 1L = 0.467 moles of HCl
We will get the mass of the 0.467 moles of HCl as follows:
mass = molar mass * number of moles = (1+35.5)*0.467 = 17.0455 grams
Now, we have the mass of the solution (water + HCl) calculated as 1230 grams and the mass of the HCl calculated as 17.0455 grams. We can use this information to get the mass of water as follows:
mass of water = 1230 - 17.0455 = 1212.9545 grams
Finally, we will get the molarity as follows:
molarity = number of moles of solute / kg of solution
molarity = (0.467) / (1212.9594*10^-3)
molarity = 0.385 mole/kg
Hope this helps :)
molarity = 0.385 moles/kg
Explanation:
Assume that the volume of the aqueous solution given is 1 liter = 1000 ml
Now, density can be calculated using the following rule:
density = mass / volume
Therefore:
mass = density * volume = 1.23 * 1000 = 1230 grams
Now, 0.467 m/L * 1L = 0.467 moles of HCl
We will get the mass of the 0.467 moles of HCl as follows:
mass = molar mass * number of moles = (1+35.5)*0.467 = 17.0455 grams
Now, we have the mass of the solution (water + HCl) calculated as 1230 grams and the mass of the HCl calculated as 17.0455 grams. We can use this information to get the mass of water as follows:
mass of water = 1230 - 17.0455 = 1212.9545 grams
Finally, we will get the molarity as follows:
molarity = number of moles of solute / kg of solution
molarity = (0.467) / (1212.9594*10^-3)
molarity = 0.385 mole/kg
Hope this helps :)
The molality of the given solution is [tex]\boxed{0.385{\text{ mol/kg}}}[/tex].
Further explanation:
Molarity:
The molarity of the solution can be defined as the concentration of the solution and is equal to the number of moles of the solute dissolved in 1 liter of the solution.
The expression of molarity (M), volume (V) and number of moles (n) is as follows:
[tex]{\text{M}}=\frac{{{\text{n}}\left({{\text{mol}}}\right)}}{{{\text{V}}\left({\text{L}}\right)}}[/tex] …… (1)
Here, V is a volume of solution in liters and n is a number of moles of solute.
Molality:
The molality of the solution can be defined as the measure of the amount of solute dissolved in one kilogram of the solvent. The expression of molality is,
[tex]{\text{m}}=\frac{{{\text{n}}\left({{\text{mol}}}\right)}}{{{\text{mass of solvent}}\left({{\text{kg}}}\right)}}[/tex] …… (2)
Here, m is a molality and n is a number of moles of solute.
The molarity of given aqueous solution of HCl is 0.467 M. This means 0.467 moles of HCl are dissolved in 1 liter of the solution.
Therefore, the mass of 0.467 moles of HCl can be calculated as follows:
[tex]\begin{gathered}{\text{Mass of HCl}}=\left({{{\text{n}}_{{\text{HCl}}}}}\right)\times\left({{\text{molar mass of HCl}}}\right)\\=\left({0.467{\text{ mol}}}\right)\times\left({36.5{\text{ g/mol}}}\right)\\=17.0455{\text{ g}}\\\end{gathered}[/tex]
Since the density of the solution is 1.23 g/mL, it means that the mass of 1 mL solution is 1.23 g. Therefore, the mass of 1 liter solution is calculated as follows:
[tex]\begin{gathered}{\text{Mass of solution}}=\left( {\frac{{1.23\;{\text{g}}}}{{1\;{\text{mL}}}}}\right)\left({\frac{{1000\;{\text{mL}}\;}}{{1\;{\text{L}}}}}\right)\\=1230\;{\text{g/L}}\\\end{gathered}[/tex]
The mass of solvent (water) is calculated as follows:
[tex]\begin{gathered}{\text{Mass of solvent}}={\text{mass of solution}}\left({aq{\text{ HCl}}}\right)-{\text{mass of solute}}\left({{\text{HCl}}}\right)\\=1230{\text{ g}}-17.0455{\text{ g}}\\{\text{=1212}}{\text{.95 g}}\times\left({\frac{{1{\text{ kg}}}}{{1000\;{\text{g}}}}}\right)\\=1.21295{\text{ kg}}\\\end{gathered}[/tex]
Substitute 1.21295 kg for mass of solvent and 0.467 number of moles of solute (HCl) in equation (2).
[tex]\begin{gathered}{\text{m}}=\frac{{{\text{n}}\left({{\text{mol}}} \right)}}{{{\text{mass of solvent}}\left({{\text{kg}}}\right)}}\\=\frac{{0.467{\text{ mol}}}}{{1.21295{\text{ kg}}}}\\=0.385{\text{ mol/kg}}\\\end{gathered}[/tex]
Therefore, molality of the given solution is [tex]{\mathbf{0}}{\mathbf{.385 mol/kg}}[/tex].
Learn more:
1. Determine the number of moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603
2. Determine how many moles of water produce: https://brainly.com/question/1405182
Answer details:
Grade: Senior school
Subject: Chemistry
Chapter: Solutions
Keywords: Molecules, elements, atom, solution, molarity, molality, hydrogen, chlorine, 0.385, 0.467 mol/L, number of moles.
