Monochromatic light with a wavelength of 6.4 E -7 meter passes through two narrow slits, producing an interference pattern on a screen 4.0 meters away. The first order bright band lines are 2.0 E -2 meters away from the central bright maxima. What is the distance between the slits?
1.3 E -4 m
8.0 E -6 m
3.2 E -9 m
7.8 E3 m

Respuesta :

Answer:

The distance between the slits is given by  1.3 × [tex]10^{-4}[/tex] m

Given:

[tex]\lambda = 6.4 \times 10^{-7} m[/tex]

D = 4 m

y = [tex]2 \times 10^{-2} m[/tex]

m = 1

To find:

distance between slits, d = ?

Formula used:

y = [tex]\frac{m \times \lambda \times D}{d}[/tex]

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

[tex]\lambda[/tex] = wavelength

Solution:

distance of first bright band from central maxima is given by,

y = [tex]\frac{m \times \lambda \times D}{d}[/tex]

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

[tex]\lambda[/tex] = wavelength

Thus,

d = [tex]\frac{m \times \lambda \times D}{y}[/tex]

d = [tex]\frac{1 \times 6.4 \times 10^{-7} \times 4 }{2 \times 10^{-2} }[/tex]

d = 1.28 × [tex]10^{-4}[/tex]

d = 1.3 × [tex]10^{-4}[/tex] m

The distance between the slits is given by  1.3 × [tex]10^{-4}[/tex] m