The answer is: Direct variation.
The explanation for this problem is shown below:
1. In direct variation, when a quantity [tex] x [/tex] varies directly as another quantity [tex] y [/tex], the value of the quantity [tex] x [/tex] increases when [tex] y [/tex] increases, and decreases when [tex] y [/tex] decreases.
2. Based on this information, let's see the expression given in the problem:
[tex] A=r^{2} [/tex]
3. As you can see, if you give values to [tex] r^{2} [/tex], the value of [tex] A [/tex] will have a direct variation. When [tex] r^{2} [/tex] increases, [tex] A [/tex] increases, and when it decreases [tex] A [/tex] decreases.
Answer : Direct Variation
Question :
Identify the variation as direct, inverse, joint or combined. A = [tex] \pi r^2 [/tex]
We know direct variation is y = kx
Where k is the constant of proportionality
When value of x increases then y also increases. when x value decreases then y value decreases.
The value of y depends on value of x It means y is directly proportional to x.
Hence A = [tex] \pi r^2 [/tex] is a direct variation.
