Respuesta :
PART A:
y = mx + C
-----------------
When x=2, y=225.
When x=5, y=480.
-----------------
Therefore:
2m + C = 225
5m + C = 480
-------------------
5*(2m+C)=5*225
2*(5m+C)=2*480
-------------------
Therefore:
10m + 5C = 1125
10m + 2C = 960
--------------
Therefore:
10m = 1125 - 5C
10m = 960 - 2C
-------------
Therefore:
960 - 2C = 1125 - 5C
3C = 165
C = 55
---------------
y=mx + 55
---------------
2m + C = 225
Therefore:
2m + 55 = 225
2m = 225 - 55
2m = 170
m = 85
-----------------
PART B:
Which means that:
y=85x + 55
-------------------
PART C & D:
Graph the equation by striking a line through the points (2,225) and (5, 480), but remember that x cannot be equal to 0, so this line shouldn't go through the point (0,0) or points whereby x is less than the value 0.
y = mx + C
-----------------
When x=2, y=225.
When x=5, y=480.
-----------------
Therefore:
2m + C = 225
5m + C = 480
-------------------
5*(2m+C)=5*225
2*(5m+C)=2*480
-------------------
Therefore:
10m + 5C = 1125
10m + 2C = 960
--------------
Therefore:
10m = 1125 - 5C
10m = 960 - 2C
-------------
Therefore:
960 - 2C = 1125 - 5C
3C = 165
C = 55
---------------
y=mx + 55
---------------
2m + C = 225
Therefore:
2m + 55 = 225
2m = 225 - 55
2m = 170
m = 85
-----------------
PART B:
Which means that:
y=85x + 55
-------------------
PART C & D:
Graph the equation by striking a line through the points (2,225) and (5, 480), but remember that x cannot be equal to 0, so this line shouldn't go through the point (0,0) or points whereby x is less than the value 0.
Part A) Sam rented a boat at $225 for 2 days. If he rents the same boat for 5 days, he has to pay a total rent of $480. Write an equation in the standard form to represent the total rent (y) that Sam has to pay for renting the boat for x days
Let
x-------> the number of days
y------> the total rent
A------> point (2,225)
B------> point (5,480)
Step 1
Find the slope AB
[tex] m=\frac{(y2-y1)}{(x2-x1)} [/tex]
[tex] mAB=\frac{(480-225)}{(5-2)} [/tex]
[tex] mAB=\frac{(255)}{(3)} [/tex]
[tex] mAB=85 [/tex]
Step 2
with m=[tex] 85 [/tex] and the point A Find the equation of the line
[tex] y-y1=m*(x-x1) [/tex]
[tex] y-225=85*(x-2) [/tex]
[tex] y=85x-170+225 [/tex]
[tex] y=85x+55 [/tex]
we know that
the equation of the line in the standard form is equal to
[tex] Ax+By=C [/tex]
so
[tex] -85x+y=55 [/tex]
therefore
the answer part 1) is
[tex] -85x+y=55 [/tex]
Part 2)Write the equation obtained in Part A using function notation
[tex] f(x)=85x+55 [/tex]
the answer Part 2) is
[tex] f(x)=85x+55 [/tex]
Part 3)Describe the steps to graph the equation obtained above on the coordinate axes. Mention the labels on the axes and the intervals.
Graph the equation by striking a line through the points [tex] (2,225) [/tex] and [tex] (5,480) [/tex]
using a graph tool
see the attached figure
