Respuesta :

taskmasters
Length of each side of a regular octagon = 8 inches
We already know the formula for finding the area of a regular octagon as
Area = 2 (1 + square root 2) * (Side)^2
         = 2 (1 + 1.414) * (8)^2
         = 2 (2.414) * 64
         = 308.99 inches ^2
         = 309 inches ^2
So the area of the regular octagon having sides of 8 inches is 309 square inches. This is the easiest method for solving these kind of problems.
boffeemadrid

Answer:

The area of the regular octagon having sides of 8 inches is 309 square inches.

Step-by-step explanation:

It is given that Length of each side of a regular octagon is 8 inches.

Now,  the formula for finding the area of a regular octagon is:

[tex]{\text}{Area}=2(1+\sqrt{2}){\times}(Side)^2[/tex]

Substituting the given values, we get

[tex]A=2(1+1.414){\times}(8)^2[/tex]

[tex]A=2(2.414){\times}64[/tex]

[tex]A=308.99{in^2[/tex]

[tex]A[/tex]≈[tex]309 in^2[/tex]

Thus, the area of the regular octagon having sides of 8 inches is 309 square inches.

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