The electric field generated by an uniformly charged wire at a distance r from the wire is given by
[tex]E(r)= \frac{\lambda}{2 \pi \epsilon _0 r} [/tex]
where [tex]\lambda[/tex] is the linear density of charge and [tex]\epsilon _0 =8.85 \cdot 10^{-12} F/m[/tex] is the electric permittivity.
In our problem, the charge density is [tex]\lambda = -94.5 \mu C/m= -94.5 \cdot 10^{-6} C/m[/tex]. We want to calculate the electric field at [tex]r=10.0 cm=0.1 m[/tex], which is
[tex]E(0.1 m)= \frac{94.5 \cdot 10^{-6} C/m}{2 \pi (8.85 \cdot 10^{-12} F/m) (0.1 m)}=1.7 \cdot 10^7 V/m [/tex]
and since the charge on the wire is negative, the field points toward the wire.
