contestada

You walk into an elevator, step onto a scale, and push the "up" button. you recall that your normal weight is 639 n . when the elevator has an upward acceleration of magnitude 2.90 m/s2 , what does the scale read?

Respuesta :

hamzaahmeds

This question deals with the concepts of the actual weight and apparent weight.

The apparent weight of the person is "827.9 N".

APPARENT WEIGHT

The apparent weight of an object is the reaction of the elevator floor on the person while the elevator is in accelerated motion. It is not the actual weight but the weight felt by the person for that time. In this case the elevator is moving up. Hence the apparent weight will be:

[tex]W_a=m(g+a)=mg+ma\\W_a=W+ma[/tex]

where,

  • W = actual weight = 639 N
  • m = mass = [tex]\frac{W}{g}=\frac{639\ N}{9.81\ m/s^2}[/tex] = 65.14 kg
  • a = acceleration = 2.9 m/s²
  • [tex]W_a[/tex] = apparent weight = ?

Therefore,

[tex]W_a=639\ N + (65.14\ kg)(2.9\ m/s^s)[/tex]

[tex]W_a=827.9\ N[/tex]

Learn more about apparent weight here:

https://brainly.com/question/26393265

Otras preguntas