Respuesta :

pls go help me at 

https://brainly.com/question/8858488 

and your answer is 5l4k^2

Answer:  The required product is [tex]\dfrac{5}{4k^2}.[/tex]

Step-by-step explanation:  We are to calculate the following product:

[tex]P=5\dfrac{k}{6}\times \dfrac{3}{2k^3}.[/tex]

We will be using the following property of exponents:

[tex]\dfrac{a^x}{a^y}=a^{x-y}.[/tex]

We have

[tex]P\\\\\\=5\dfrac{k}{6}\times\dfrac{3}{2k^3}\\\\\\=\dfrac{5}{6}\times\dfrac{3}{2}k^{1-3}\\\\\\=\dfrac{5}{4}k^{-2}=\dfrac{5}{4k^2}.[/tex]

Thus, the required product is [tex]\dfrac{5}{4k^2}.[/tex]

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