Respuesta :
ab + bc + b² + ac =
(b² + bc)+(ab + ac) =
b(b+ c)+a(b + с) =
(b + c)(b + a)
(b² + bc)+(ab + ac) =
b(b+ c)+a(b + с) =
(b + c)(b + a)
(ab + b^2) + (bc + ac).
{So we can get the terms with the same variables together}
Factoring out the GCF from each term:
b(a + b) + c(a + b).
Then, factoring out a + b yields:
(a + b)(b + c).
I hope this helps!
{So we can get the terms with the same variables together}
Factoring out the GCF from each term:
b(a + b) + c(a + b).
Then, factoring out a + b yields:
(a + b)(b + c).
I hope this helps!