In order to solve the problem, we can use Stevin's law. The pressure at the bottom of a column of fluid with density [tex]\rho[/tex] and height h is:
[tex]p=\rho g h[/tex]
In our problem, the fluid is water, so its density is [tex]\rho = 1000 Kg/m^3[/tex]. The height of the column of water is h=60 m, and [tex]g=9.81 m/s^2[/tex], therefore
[tex]p=(1000 Kg/m^3)(9.81 m/s^2)(60 m)=5.89 \cdot 10^5 Pa[/tex]
