Given the points are A(3, 2) and B(6, 4).
If it is asking about the slope of the line AB, then we can use the slope formula as given by :-
[tex] Slope, \;m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} [/tex]
where (x₁, y₁) = A(3, 2) and (x₂, y₂) = B(6, 4)
[tex] m = \frac{4-2}{6-3} =\frac{2}{3} [/tex]
Hence, m = 2/3 would be slope of the line AB.
If it is asking about the y-intercept of the line AB, then we can use slope-intercept form as given by :-
y = mx + b
where m is the slope and b is the y-intercept.
we can plug the value of m = 2/3 and point A(3, 2) into the equation and solve for b.
[tex] 2=(\frac{2}{3} )(3) +b \\\\
2 = 2 + b \\\\
b = 0 [/tex]
Hence, b = 0 would be y-intercept of the line AB.
If it is asking for the equation of the line AB, then we can use slope-intercept form and put values of m = 2/3 and b = 0.
y = mx + b
[tex] y=\frac{2}{3} x+0 \\\\
y=\frac{2}{3} x \;\;
or\;\; 3y=2x [/tex]
Hence, [tex] y=\frac{2}{3} x \;\;
or\;\; 3y=2x [/tex] would be equation of the line AB.
