Calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH–] is 1 x 10–11 mol/L. Is this solution acididc, basic, or neutral? Show your work.

Please help thanks so much! :)

Respuesta :

pOH = -log [OH-]
pOH = - log (1 x 10^-11)
pOH = -(-11) = 11

pH + pOH = 14
pH + 11 = 14
pH = 14 - 11 = 3

we have been given the [OH⁻] therefore we can first find the pOH value

pOH scale is used to determine the basicity of a solution

pOH = - log [OH⁻]

pOH = - log (1 x 10⁻¹¹ M)

pOH = 11

after knowing the pOH we can calculate pH using following equation

pH + pOH = 14

since pOH = 11

pH = 14 - 11

pH = 3

pH scale is used to determine how acidic a solution is



once pH is known we can can calculate Hydrogen ion concentration

pH = - log [H⁺]

[H⁺] = antilog (-pH)

[H⁺] = antilog(-3)

[H⁺] = 1 x 10⁻³ M


if pH is less than 7 - solution is acidic

pH = 7 the solution is neutral

pH more than 7 - solution is basic


pH of solution is 3 which is less than 7

therefore solution is acidic

and hydrogen ion concentration is 1 x 10⁻³ M