For this case what we should see are the values for which the function is not defined. So we have to study your domain: g (x) = x ^ 3 / (x-2) (x + 1) We see what values make the denominator is not defined: (x-2) (x + 1) = 0 First value: x-2 = 0 x = 2 Second value: x + 1 = 0 x = -1 The function has two vertical asymptotes: x = 2 x = -1 Answer: a. x = 2, x-1