Respuesta :
Drawing a diagram to match this figure, BC would have to be the hypotenuse as it is the longest side of the triangle. Angle A would have to be the right angle.
For the first choice, [tex]\cot B = \frac{1}{ \tan B} \\ = \frac {1}{\frac {6}{5}} \\ = 1 \div \frac{6}{5} = \frac{1}{1} \div \frac{6}{5} \\ = \frac{1}{1} * \frac{5}{6} = \frac{5}{6}[/tex]. The first choice is not correct.
The second choice gives us [tex]\csc C= \frac{1}{ \sin C}= \frac{1}{\frac {5}{8}} \\ = 1 \div \frac{5}{8} = \frac{1}{1} \div \frac{5}{8} \\ = \frac{1}{1} * \frac{8}{5} = \frac{8}{5}[/tex]. The second choice is not correct either.
The third choice gives us
For the first choice, [tex]\cot B = \frac{1}{ \tan B} \\ = \frac {1}{\frac {6}{5}} \\ = 1 \div \frac{6}{5} = \frac{1}{1} \div \frac{6}{5} \\ = \frac{1}{1} * \frac{5}{6} = \frac{5}{6}[/tex]. The first choice is not correct.
The second choice gives us [tex]\csc C= \frac{1}{ \sin C}= \frac{1}{\frac {5}{8}} \\ = 1 \div \frac{5}{8} = \frac{1}{1} \div \frac{5}{8} \\ = \frac{1}{1} * \frac{8}{5} = \frac{8}{5}[/tex]. The second choice is not correct either.
The third choice gives us
