The rule to solving these is to get x on its own by performing 'operations'. However, whatever we do the left-hand side we must also do to the right hand side. So,
[tex]3x+9=27[/tex], firstly that +9 is messing up the x so we take away 9 from the left to get rid of it but also take away 9 on the right because we have to.
[tex]3x+9-9=27-9 \Rightarrow 3x=18[/tex], next see that the 'times 3' is messing up the x so we divide the left-hand side by 3 to get rid but then also divide the right hand side because we have to.
[tex]3x \div3=18\div 3 \Rightarrow x=6[/tex] and then you have your solution.
Questions like this are all about figuring how to get the x on it's own but also remembering to do whatever you do on BOTH sides of the equals. Hope this helps.
