Answer:
Please find the attached file.
Step-by-step explanation:
Given: [tex]y=\dfrac{8}{x+3}-2[/tex]
We need to draw the graph of function with asymptote.
For horizontal asymptote:-
[tex]x\rightarrow \infty[/tex]
[tex]y=\lim_{x\rightarrow \infty}(\dfrac{8}{x+3}-2)=-2[/tex]
HA: y=-2
For vertical asymptote:-
[tex]y\rightarrow \infty[/tex]
[tex]x+3=0[/tex]
VA: x=-3
For x-intercept, Put y=0
(1,0)
For y-intercept, Put x=0
(0,2/3)
Now we will plot on graph and draw the graph.
Please see the attachment for graph.
