Respuesta :

Answer: Value of A is 2 and value of B is 1.

Explanation:

Lithium is the third element of the periodic table. It belongs to the Period 2 and Group 1 and is considered as an alkali metals.

To write the electronic configuration, we need to find the number of electrons this element contain, which is equal to the atomic number.

Number of electrons = Atomic number = 3

So, the electronic configuration will be: [tex]1s^22s^1[/tex]

The s-orbital in total can contain only 2 electrons.

Hence, the value of A is 2 and value of B is 1.

The periodic table showcases the table of the chemical elements listed in order of atomic number, usually in rows(period) from the left to the right, in such a way that elements with similar atomic structures as well as similar chemical properties can be located in vertical columns (groups).

Lithium is the third chemical element on the periodic table. It can be located on group 1 element also known as the alkali metals. It is soft in nature and has a whitish color.

The electronic configuration explains how electrons are distributed in their atomic orbitals.

The electronic configuration for Lithium can be expressed as:

Li: 1s² 2s¹

Therefore, from the given information, we can conclude that the value for the electronic configuration of A and B  in the Lithium sample given is 2 and 1 respectively

Learn more about electronic configuration here:

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