Respuesta :
Answer : The correct option is, 0.2 mole Y left over .
Explanation : Given,
Moles of X = 4.8 mole
Moles of Y = 3.4 mole
The balanced chemical reaction is,
[tex]3X+2Y\rightarrow X_3Y_2[/tex]
From the balanced reaction, we conclude that
As, 3 moles of X react with 2 moles of Y
So, 4.8 moles of X react with [tex]\frac{2}{3}\times 4.8=3.2[/tex] moles of Y
From this we conclude that, the reactant Y is an excess reagent and X is a limiting reagent.
The moles of excess reagent left over at the end of the reaction = Given moles of X - Required moles of X
The moles of excess reagent left over at the end of the reaction = 3.4 - 3.2 = 0.2 mole
Therefore, the moles of excess reagent left over at the end of the reaction is, 0.2 mole Y left over.
Answer:
The correct answer is : '0.2 mol Y left over'.
Explanation:
[tex]3X + 2Y \rightarrow X_3Y_2[/tex]
Moles of X = 4.8 moles
Moles of Y = 3.4 moles
According to reaction, 3 moles of X react with 2 moles of Y .
Then 4.8 moles of X react with :
[tex]\frac{2}{3}\times 4.8=3.2 [/tex]moles of Y
Moles of Y reacted = 3.2 moles
Moles of Y left unreacted = 3.4 moles - 3.2 moles = 0.2 moles
As we can see that X is in limiting amount and y is present in an excessive amount.And the left over amount of Y is 0.2 moles.
