Respuesta :
The tension of the cord is the centripetal force that keeps the ball in circular motion:
[tex]T=F_c = m \frac{v^2}{r} [/tex]
where T is the tension of the cord, [tex]F_c[/tex] is the centripetal force, [tex]m=0.55 Kg[/tex] is the mass of the ball, v its speed and [tex]r=1.3 m[/tex] is the radius of the circle.
The maximum allowed tension is T=75 N, before the cord breaks. Using this value inside the formula, we can find which is the maximum allowed value fot the speed v:
[tex]v= \sqrt{ \frac{T r}{m} }= \sqrt{ \frac{(75 N)(1.3 m)}{(0.55 kg)} }=13.3 m/s [/tex]
[tex]T=F_c = m \frac{v^2}{r} [/tex]
where T is the tension of the cord, [tex]F_c[/tex] is the centripetal force, [tex]m=0.55 Kg[/tex] is the mass of the ball, v its speed and [tex]r=1.3 m[/tex] is the radius of the circle.
The maximum allowed tension is T=75 N, before the cord breaks. Using this value inside the formula, we can find which is the maximum allowed value fot the speed v:
[tex]v= \sqrt{ \frac{T r}{m} }= \sqrt{ \frac{(75 N)(1.3 m)}{(0.55 kg)} }=13.3 m/s [/tex]
The force act on the body tries to attract the body inward towards the circle when the body is executing circular motion. The maximum value of speed will be 13.3 m/sec.
What is centripetal force?
The force operating on an object in curvilinear motion directed toward the axis of rotation or center of curvature is known as centripetal force.
Newton is the unit of centripetal force.
The centripetal force is always perpendicular to the direction of displacement of the item. The centripetal force of an item traveling on a circular route always works towards the center of the circle.
Due to rotation, the tension is act in the chord which is equal to the centripetal force act the ball.
[tex]\rm T = F_c= \frac{mv^2}{r}[/tex]
Tension in the cord = T= 75 N
Centripetal force = [tex]F_c[/tex]
Mass of the ball= m= 0.55 Kg
Linear speed =v= ?
The radius of the circle.= r = 1.3 m
T is the maximum tension before the cord breaks. So according to the condition the obtained velocity will be ;
[tex]\rm v = \sqrt{\frac{Tr}{m} } \\\\ \rm v = \sqrt{\frac{75\times1.3}{0.55} }\\\\ \rm v = 13.3 \;m/sec[/tex]
Hence the maximum value of speed will be 13.3 m/sec.
To learn more about the centripetal force refer to the link;
https://brainly.com/question/10596517
