contestada

When a clock reads 5.0 seconds a cart's velocity in the negative x direction is 3.0 m/s. when the clock reads 6.0 seconds, the cart's velocity in the positive x direction is 4.0 m/s. what is the magnitude (in m/s2) of the average acceleration of the cart?

Respuesta :

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Impulse is the change of momentum before and after the collision:
I = mv₁ - mv₂ = m (v₁-v₂)
m mass
v velocity

Impuls also is defined as the average force during a short period of time:
I = F * t = m * a * t
F average force
t time difference
m mass
a average acceleration

Combined:
m(v₁- v₂) = m * a * t
a = (v₁- v₂) / t
= (4m/s - (-3m/s)) / 6s - 5s
= 7m/s / 1s
= 7 m/s²

The kinematic we find the average acceleration of the body is 7 m/s²

Given parameters

  • The velocity at two instant of time t₁ = 5.0 s, v₁ = -3.0 m / s

           t₂= 6.0 s,  v₂ = 4.0 m / s

To find

  • The average acceleration of the body

Kinematics studies the movement of the carpus, establishing relationships between their position, speed and acceleration.

Average acceleration is defined as the change in velocity in a given time interval

             a_ {avg} = [tex]\frac{\Delta v}{\Delta t}[/tex]

Let's apply this expression to our case

let's set a reference frame where the positive direction of the x axis is positive, so v₁ is negative

         

             a_ {avg} = [tex]\frac{v_2 -v_1}{t_2 -t_1}[/tex]

             a_ {avg} = [tex]\frac{4- (-3)}{6-5}[/tex]

             a_ {avg} = 7 m / s²

In conclusion using kinematics we find the average acceleration of the body is 7 m / s²

learn more about average acceleration here:

https://brainly.com/question/17355747

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