Respuesta :
Answer: The molality of solution is 1.94 m.
Explanation:
We are given:
Mass of sulfuric acid = 17.75 grams
Volume of solution = 100 mL
Density of solution = 1.1094 g/mL
To calculate the mass of solution, we use the equation:
[tex]Density=\frac{Mass}{Volume}[/tex]
Putting values in above equation, we get:
[tex]1.1094g/mL=\frac{\text{Mass of solution}}{100mL}[/tex]
[tex]\text{Mass of solution}=110.94g[/tex]
Mass of solvent = Mass of solution - Mass of solute
Mass of solvent = 110.94 - 17.75 = 93.19 g
To calculate the molality of solution, we use the equation:
[tex]Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}[/tex]
Where,
[tex]m_{solute}[/tex] = Given mass of solute [tex](H_2SO_4)[/tex] = 17.75 g
[tex]M_{solute}[/tex] = Molar mass of solute [tex](H_2SO_4)[/tex] = 98 g/mol
[tex]W_{solvent}[/tex] = Mass of solvent = 93.19 g
Putting values in above equation, we get:
[tex]\text{Molality of }H_2SO_4=\frac{17.75\times 1000}{98\times 93.19}[/tex]
[tex]\text{Molality of }H_2SO_4=1.94m[/tex]
Hence, the molality of solution is 1.94 m.
