Find the proportion of heights that are within 1 standard deviation of the sample mean and also the proportion that are within 2 standard deviations of the sample mean. use the unrounded values for the mean and standard deviation when doing this calculation. give your answers as decimals to 2 decimal places.

For a normal distribution only, for a population, not for particular sample.

proportion between 1 standard deviation, independent of μ and σ , is given by:
P(Z<1)-P(Z<-1)
=0.841345-0.158655=0.682689
=0.68 (to two places of decimal)

proportion between 2 standard deviations, independent of μ and σ , is given by:
P(Z<2)-P(Z<-2)
=0.977250-0.022750=0.954500=0.95 (to two places of decimal)

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raphealnwobi raphealnwobi · Answer 2 · 2022-02-15T11:46:30+01:00

68% of heights that are within 1 standard deviation of the sample mean and 95% are within 2 standard deviations of the sample mean.

Empirical rule

Empirical rule states that for a normal distribution, 68% of the values are within one standard deviation from the mean, 95% of the values are within two standard deviation from the mean, 99.7% of the values are within three standard deviation from the mean

Using empirical rule:

68% of heights that are within 1 standard deviation of the sample mean and 95% are within 2 standard deviations of the sample mean.

Find out more on Empirical rule at: https://brainly.com/question/10093236