devariuskhickma
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In a certain skyscraper, the elevator whisk you a restaurant in the skyscraper at a speed of 500 feet in 60 seconds. If the restaurant is 300 feet up, how long will it take you to reach the restaurant by elevator?

Respuesta :

[tex]\bf \begin{array}{ccll} feet&seconds\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 500&60\\ 300&x \end{array}\implies \cfrac{500}{300}=\cfrac{60}{x}\implies \cfrac{5}{3}=\cfrac{60}{x}\implies x=\cfrac{3\cdot 60}{5}[/tex]

Answer:

The elevator will take you up at 300 feet in 36 seconds.

Step-by-step explanation:

Let the time taken to go up 300 feet be = t seconds

Given is that the elevator takes you up at 500 feet in 60 seconds.

So, we can derive a relation as:

[tex]\frac{500}{60}= \frac{300}{t}[/tex]

=> [tex]500t=300\times60[/tex]

=> [tex]500t=18000[/tex]

t = 36 seconds

So, the elevator will take you up at 300 feet in 36 seconds.

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