Respuesta :
let hotdogs be d and hamburgers be b
he needs AT LEAST 3 packages of hotdogs
so
[tex]d \geqslant 3[/tex]
each packet costs $5 so he must spend $15 in total on hotdogs
so he can spend NO MORE than $45 on hamburgers so can buy no more than 4 packs of hamburgers
so
[tex]b \leqslant 4[/tex]
he needs AT LEAST 3 packages of hotdogs
so
[tex]d \geqslant 3[/tex]
each packet costs $5 so he must spend $15 in total on hotdogs
so he can spend NO MORE than $45 on hamburgers so can buy no more than 4 packs of hamburgers
so
[tex]b \leqslant 4[/tex]
Answer:
10x + 5y ≤ 60 & y ≥ 3
Step-by-step explanation:
Let x = the number of hamburgers
Let y = the number of hotdogs
Let us first represent the amount of food:
10x + 5y ≤ 60
This means x packages of $10 hamburgers plus y packages of $5 hotdogs is greater than or equal to $60.
However, we have also been given another important piece of information and that is that he must buy at least three packages of hotdogs.
y ≥ 3
this means that the packages of hotdogs must be no less than 3.
Hence or two inequalities are 10x + 5y ≤ 60 & y ≥ 3.
This also means that the least he can spend on hotdogs is $15. The most he can spend on hamburgers is $45, meaning the most packages of hamburgers he can get is 4
PLEASE MARK BRAINLIEST